Question

given that
with
method
Factorise x² + 13x²+20; if its
1+2 ts its factors
the use
of long division​

Answer 1

Answer:

The value of x

3

+13x

2

+32x+20 is

x

3

+x

2

+12x

2

+12x+20x+20

=x

2

(x+1)+12x(x+1)+20(x+1)

=(x−1)(x

2

+12x+20)

=(x−1)(x

2

+10x+2x+20)

=(x+1)[x(x+10)+2(x+10)]

=(x+1)(x+2)(x+10)

I can slove your questions plz make me brillianlist plz