Given that X^2018.Y^2017=1/2 and X^2016.Y^2019=8, the value of X²+Y³=?
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Factor 4x^2-49 | Mathway
Factor 4x^2-49 | MathwayRewrite 4x2 4 x 2 as (2x)2 ( 2 x ) 2 . Rewrite 49 as 72 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=2x a = 2 x and b=7 .
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