Given that (x + 3) is a factor of 6x3 - bx2 +18 find the value of b
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X+3=0
X=-3
Put in equation the value of x
6(-3)^3-b(-3)^2+18=0
= -162 - b(-27)+18=0
= -162+27b +18=0
= -144+b27=0
= b27=144
=> b = 144/27
X=-3
Put in equation the value of x
6(-3)^3-b(-3)^2+18=0
= -162 - b(-27)+18=0
= -162+27b +18=0
= -144+b27=0
= b27=144
=> b = 144/27
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