Question

Given that x=-4 and y=2, evaluate the following: -5x+3y²=

Answer 1

• As per the data given in the question, we have to find the value of the expression.

      Given data:- $-5x+3y^{2}.\ where\ x=-4\ and\ y=2.$

       To find:- value of the expression.

       Solution:-

• Here, we will use the below following steps to find a solution using the transposition method:
• Step 1:- we will Identify the variables and constants in the given simple equation.
• Step 2:-then we Simplify the equation in LHS and RHS.
• - Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.
• Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.
• Step 5:- Then the result will be the solution for the given linear equation.

     So, simply we substitute the value in the given expression, we get,

      $=-5x+3y^{2}\\=-5(-4)+3\times(2)^{2} \\=20+3\times4\\=20+12\\=32.$

  Hence, the value will be $32.$

Answer 2

As we know that the data given below is provided in the question,

In the above question, it is given that,

The given equation in the question is -5x+3y².

Where x=-4 and y=2

Here we have to simplify the given equation.

We have to use the substitution method and simplify it.

Thus, substitute the value of x and y in the given equation.

$\begin{array}{l}=-5(-4)+3 \times(2)^{2} \\=20+3 \times 4 \\=20+12 \\=32 .\end{array}$

Hence after evaluating the given equation we get the value as 32.