given that x-5 is a factor of a cubic polynomial x³-3√5x²+13x-3√5 find all the zeroes of the polynomial
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Answer:
x3-3√5x2+13x-3√5
Sum of zeroes=-b/a=-(-3√5x2)/1=3√5x2
Sum of zeroes other than two=c/a=13/1=13
Product of zeroes=-d/a=-(-3√5)/1=3√5
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