Question

given that x-5 is a factor of a cubic polynomial x³-3√5x²+13x-3√5 find all the zeroes of the polynomial​

Answer 1

Answer:

x3-3√5x2+13x-3√5

Sum of zeroes=-b/a=-(-3√5x2)/1=3√5x2

Sum of zeroes other than two=c/a=13/1=13

Product of zeroes=-d/a=-(-3√5)/1=3√5