Given that x-√5 is a factor of x3-3√5 x 2-5x+15√5 find all the zeros of the polynomial
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p(x)=x^3-3√5x^2-5x+15√5
g(x)=x-√5
the zero of the polynomial of x-√5 is 0
x-√5=0
x=√5
p(√5)=(√5)^3-3√5(√5)^2-5(√5)+15√5
=25√5-75√5-5√5+15√5
= -40√5
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