Question

given that x is 30% greater than p and y is 60% greater than q. by how much % is xy greater than pq

Answer 1

Answer:

high percentage

Step-by-step explanation:

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Answer 2

xy is 108% greater than pq.

Step-by-step explanation:

Consider the provided information.

x is 30% greater than p.

Therefore x=p+30% of p

$x=p+\frac{30}{100}\times p\\x=1.3p$

Similarly, y is 60% greater than q.

$y=q+\frac{60}{100}\times q\\y=1.6q$

Now the product of xy in terms of pq is:

$xy=1.3p\times1.6q=2.08pq$

Now we need to find the percentage.

$Percentage=\dfrac{2.08pq-pq}{pq} \times 100\\\\Percentage=\dfrac{pq(2.08-1)}{pq} \times 100\\\\Percentage=(2.08-1)\times 100\\Percentage=(1.08)\times 100\\Percentage=108$

Hence, xy is 108% greater than pq.

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