Given that x, is inversely proportional to y^2 and z^3, and x=1 when y=3 and z=2. Find the value of z when x=9 and y=1
Answers
Answered by
0
A/c to the question:
Y ∝ 1/x
y= k x …(1)
where k=constant
value of k from (1)
k= (y) (x)
let again:
before change
K= (y1) (x1) … (2)
after change
K= (y2) (x2) …(3)
equating (2) and (3), we get
(y1) (x1) = (y2) (x2) …(5)
here we are given:
x1= 4
y1= 3
x2=8
y2=?
by rearranging (5) for y2
y2= (y1) (x1) / (x2)
y2= (3) (4) / (8)
y2= { (3) (4) } / { (4) (2) }
four four get cancel
y2=3/2 =1.5 (Answer)
Similar questions