given that x=log3 base is 2 and y=log 5 base is 2 then express log 7.5 in terms of x and y
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[tex] log_{2}(7.5) = log_{2}(15 \div 2) \\ = > log_{2}(15) ... in terms of x and y .if x= log 3 base 2 y= log 5 base 2.i.) log 7.5 ... if you liked it then mark it as brainliest answer.
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