Question

Given that x -root 5 is a factor of the polynomial x cube -3 root 5 x square-5x +15 root 5. Find all the zeroes of the polynomial.

Answer 1

Let, p(x)=x³-3√5x²-5x+15√5
∵, (x-√5) is a factor of p(x); 
∴, One zero of p(x) is √5.
Now, p(x)
=x³-3√5x²-5x+15√5
=(x-√5)(x²-2√5x-15)
=(x-√5)(x²-3√5x+√5x-15)
=(x-√5){x(x-3√5)+√5(x-3√5)}
=(x-√5)(x-3√5)(x+√5)
Then other two zeros of p(x) are:
3√5 and -√5

Answer 2

Answer:

this answer

Step-by-step explanation:

Then other two zeroes of p(X) are:

3√5 and -√5

I hope this answer help you