given that x-root5 is a factor of polynomial x³-3root5x²-5x+15root5. find all the zeros of the polynomial
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x³-3√5x²-5x+15√5
= x²(x-√5)-5(x-√5)
=(x²-5)(x-√5)
=(x+5)(x-5)(x-√5)
hence the roots are 5,-5,√5
= x²(x-√5)-5(x-√5)
=(x²-5)(x-√5)
=(x+5)(x-5)(x-√5)
hence the roots are 5,-5,√5
Answered by
0
Answer:
Hey, here your answer
Step-by-step explanation:
x^2-root5x - 15
x^2-3root5 + root5x - 15
x(x-3root5) + root5(x-3root5)
x=3root5 & x= -root5
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