Question

Given that, x(x+1)=1, then find the
value
of tija -
(2431​

Answer 1

Answer:

x^2+x=1

x^2+x+(-1)=0

a=1 b=1 c=-1

D =b^2-4ac

D=(1)^2-4(1x-1)

D=1+5

D=6

it has real and distinct roots .

Step-by-step explanation:

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