Question

given that x+y = 13 and xy = 40 , find the value of x - y ​

Answer 1

Answer:

x-y=3

Step-by-step explanation:

x+y=13

(x+y)^2=169

x^2+y^2+2xy=169

x^2+y^2+80=169

x^2+y^2=89

Similarly,

(x-y)^2=x^2+y^2-2xy

(x-y)^2=89-80

(x-y)^2 =9

x-y=3..

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Answer 2

Answer:

(x+y)^2=x^2+y^2+2xy

13^2=x^2+y^2+2*40

169-80=x^2+y^2

89=x^2+y^2

(x-y)^2=89-2*40

x-y=under root 9

=3

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