Question

Given that
x+y = 8,
x²+y²= 34.
Can you find out the values of X and Y separately?​

Answer 1

Answer:

x=5 and y=3

Step-by-step explanation:

5+3=8

5sq+3sq=34

25+9=34

Answer 2

Answer:

y=8-x

${x}^{2} + (8 - x) ^{2}$

x2+64+x2-16x=34

2x2-16x+30=0

2x2-10x-6x+30=0

2x(x-5)-6(x-5)=0

x=3,3

y=8-x=5