Question

Given that x²+2x-3 is a factor of f(x)=
x⁴+6x³+2ax²+bx-3a. Find the values of a and b.​

Answer 1

Answer:

a=5 , b=-2

Step-by-step explanation:

$x^{2} +2x-3$ is factor

so (x-1) (x+3) are factors too

Thus substituing there values as x

P(1)=0 ; x⁴+6x³+2ax²+bx-3a=0

we get equation b=a-7

P(-3)=0; x⁴+6x³+2ax²+bx-3a=0

we get second equation 15a-3b=81

now putting value of b into second equation we get 15a-3(a-7)= 81

12a=60

a=5

now b=a-7; b=5-7=-2

Answer provided by gauthmath

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