Question

given that y is equals to 2 when x is equals to 1 and x varies inversely as square of y then find the value of x for y is equals to 6​

Answer 1

$\huge\red{\sf Nmste}$

Given x is inversely prop as the sq. of y.so if we take k as constant of variation then,

x=k*1/y^2

now putting the initial values of x and y we get,

4=k*1/9 or k =36

so the law of variation becomes x=36*1/y^2

now putting the value of y=6 in this equation we get,

x=36*1/6^2 or x=36*1/36=1

so,x=1 when y=6.

Answer 2

Answer:

Given that x varies inversely to the square of y

x²=1/y

y=6

x=(1/6)-½

X=0.41 approx