Question

Given that y varies directly with x and inversely with z; and x = 8 when y = 16 and z = 10; find y when x = 12 and z = 6.

Answer 1

Answer:

y=Kx

16=k8

k=16/8=2

y=2x

y=2×12=24

y=c/z

2x=c/z

2×8=c/10

c=160

y=160/z

y=160/6