Question

Given that,
Zn++ + 2e → Zn E°= -0.76V
Mg +2e → Mg E° = -2.37 V
When Zn dust is added to MgCl2 solution then
(a) Zn is dissolved
(b) ZnCl2 is formed
(c) Mg is crystallized out (d) No reaction

Answer 1

Answer:

thhssasssar do z a hhxh ki rrccsss