Given the answer pls
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7.)36
2×18
2×2×9
2×2×3×3....
9.)14, 15, 16); (20, 21, 22); (24, 25, 26); (32, 33, 34); (33, 34, 35); (34, 35, 36); (38, 39, 40); (44,45,46); (48, 49, 50); (50, 51, 52); (54, 55, 56); (55, 56, 57); (56, 57, 58); (62, 63, 64); (63, 64, 65); (64, 65, 66): (68, 69, 70); (74, 75, 76); (76, 77, 78), (80, 81, 82); (84, 85, 86); (85, 86, 87); (86, 87, 88); ...
10.)2 whole number that are neither prime nor composite are 0 and 1.
sunnysarb00:
Also given the 8,9,10answer pls
So, let's assume b = 24 and a = 3
then a = 3 will be a factor of 48, 72, 96 etc. You can see that the multiples of 24:- 48, 72, 96 etc all are completely divisible by a = 3. Thus proved that any factor of a number is always a factor of all multiples of that number.
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