Question

Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n?

Answer 1

4-3(n-1)
4-3n+4
4+4-3n
8-3n answer

Answer 2

The domain for $\boldsymbol{n} \geq \mathbf{1}$ for given arithmetic sequence $\bold{a_{n}=4-3(n-1)}$

Solution:

To find the domain of n in the arithmetic sequence given is 4 − 3(n − 1), we follow as below,

Now as we know that $a_{n}=4-3(n-1)$  

$\bold{a_{n}=a-d(n-1)}$

First number of the series - a

Difference of the series - d

The behavior or the affinity of the pattern depends upon whether d is positive or negative, positive then domain stretches to positive infinity, if negative then negative infinity.  

In this case d = 3 positive, the domain of the series is $\boldsymbol{n} \geq \mathbf{1} .$