Question

Given the bond energies $N \equiv N$, H – H and N – H bonds are 945,436 and 391 kJ mole⁻¹ respectively, the enthalpy of the following reaction $N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)$ is
(a) –93 kJ
(b) 102 kJ
(c) 90 kJ
(d) 105 kJ

Answer 1

(b) part is the correct option