Question

Given the circle x²+y²-2x+4y=o. Find the equation of its
diameter which passes through the origin.​

Answer 1

Answer:

2x + y = 0

Step-by-step explanation:

2x + y = 0  

Let the diameter of the circle be y = mx.

Since the diameter of the circle passes through its centre, (1, −2) satisfies the equation of the diameter.

∴m=-2

Substituting the value of m in the equation of diameter:

y= -2x

=> 2x+y=0

Hence, the required equation of the diameter is

2x+y=0