Question

Given the circuit on right find. The volatage drop across the 4 ohm resistors
The voltage drop across the 5 ohm resistors
Te current through 2ohm resistors
The current through 7 ohm resistors​

Answer 1

Answer:

let's find from last.

the current through 7 ohm resistor

we know that ohms law is V=IR

SO, CURRENT IS I=V/R

SUBSTITUTE V=12 AND R=7

I=12/7

I=1.71 A

THE CURRENT THROUGH 2 OHM RESISTOR

WE KNOW THAT OHMS LAW IS V=IR

I=V/R

SUBSTITUTE V=12 AND R=2

I=12/6

I=2 A

THE VOLTAGE DROP ACROSS 5 OHM RESISTOR

WE KNOW THAT THERE IS NO VOLTAGE DIVISION IN PARALLEL ARRANGEMENT

WE ALSO KNOW THAT THERE IS NO DIVISION OF CURRENT IN SERIES ARRANGEMENT

SO, THE CURRENT PASSING THROUGH 7 OHM AND 5 OHM RESISTORS IS SAME

WE KNOW THAT THE CURRENT IN 7 OHM RESISTOR IS 1.71 A, SO THE CURRENT IN 5 OHM RESISTOR IS ALSO 1.71 A. SO, BY OHMS LAW, V=IR

SUBSTITUTE I=1.71 AND R=5

V=1.71×5

V=8.55 V

THE VOLTAGE DROP IN 4 OHMS RESISTOR

WE KNOW THAT THERE IS NO VOLTAGE DIVISION IN PARALLEL ARRANGEMENT

HERE THERE IS NO SERIES ARRANGEMENT.

SO THE VOLTAGE REMAINS THE SAME

V=12 V