Question

Given the complex number z = 1 - j .By De'Moivres Theorem $z^{4}$ is:

Answer 1

Answer:

${z} = \sqrt{ {1}^{2} + ( { - 1)}^{2} } \\ = \sqrt{2} \\ \\ so \: \: \\ {z}^{4} = ( { \sqrt{2} )}^{4} \\ = 4$

${z}^{n} = {r}^{n} {e}^{i \times n \theta}$