Given the dimensions of the following polygons, find the area of each of the following.
(a) Triangle of base (2x-2y) units and height (x + y) units
(b) Rectangle of sides (4a +5b) units and (4a-5b) units
(C) Square of side (5a + b) units
[Hint:Area of triangle 1/2 * Base x Height]
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(a)
Area of triangle=1/2*b*h
=1/2*2(x-y)*(x+y)
=(x-y)(x+y)
=(x-y)^2
(b)
Area of rectangle=l*b
=(4a+5b)(4a-5b)
=(4a-5b)^2
(c)
Area of square=side^2
side=4a-5b
Area=(4a-5b)^2
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Answer:
Area of triangle
1/2×b×h
1/2×2x-2y×x+y=2x is answer
Area of rectangle
l×b
(4a+5b) (4a-5b)
a+b ×a-b=a²-b²
(4a) ²-(5b) ²
16a²-25b²
Area of square
4×side
4(5a+b)
20a+4b
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