Question

given the direct proof to show the product of two perfect squares is also a perfect squares

Answer 1

mn = (2k + 1)(2l + 1) by our definitions of m and n = 4kl + 2k + 2l + 1 by expanding the brackets = 2(2kl + k + l)+1 since 2 is a common factor. Let m and n be integers. Directly prove that if m and n are perfect squares then mn is also a perfect square. ... Now assume that m and n are integers and are perfect squares.

Step-by-step explanation:

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