given the domain {-2,-1,0,1,2}, determine the range for each expression,use a table of values 3. f(x)=2x-1/2 4. y=(x²-1)/x 5. x=y-3
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Domain for expression f(x)= 2x-1/2 is {-9/2, -5/2, -1/2, 3/2, 7/2 } .
That's for expression x= y - 3 is {1,2,3}.
While for expression y=(x²-1)/x given domain is incorrect because x can't be substituted by zero here to avoid the indeterminate form upon putting x in denominator. And for a function to exist every element of the domain must lead us to some image.
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