Question

Given the electric field in the region e is equal to 2x icap to find the net electric flux through the q and a charge enclosed by it

Answer 1

The net charge enclosed by the cube is 2a³ε₀

Explanation :

Given, E = 2x i

Since the electric field has only x component, hence only the two sides which are perpendicular to x axis will have flux, flux through rest of the faces = 0

Field at the 1st face E₁ = 2x = 2 x 0 = 0    ( as x = 0 here)

Field at the 2nd face E₂ = 2x = 2a    ( as x = a)

hence net field = 0 + 2a = 2a

We know that flux is given as,

Φ = E.S = 2a x a² = 2a³

Applying gauss law,

Φ = q/ε₀

=> q = Φε₀

=> q = 2a³ε₀

Answer 2

Answer:

Answer number 40

Explanation: