Given the electrode potentials
Fe³⁺ + e⁻ → Fe²⁺, E° = 0.771 volts
I₂ + 2e⁻ → 2I⁻, E° = 0.536 volts
E°꜀ₑₗₗ for the cell reaction
2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂, is
(a) 1.006 V (b) 0.503 V
(c) 0.235 V (d) –0.235 V
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Answered by
9
Explanation:
Given the electrode potentials
Fe³⁺ + e⁻ → Fe²⁺, E° = 0.771 volts
I₂ + 2e⁻ → 2I⁻, E° = 0.536 volts
E°꜀ₑₗₗ for the cell reaction
2Fe³⁺ + 2I⁻ → 2Fe²⁺ + I₂, is
(a) 1.006
(b) 0.503 V✔️✔️
(c) 0.235 V
(d) –0.235 V
Answered by
3
(b) 0.503 V
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