Question

Given the equation 1+2+3+..+n == n (n+1)/2 what is its formation in hypothetical step ?

Answer 1

Answer:

1.5

Explanation:

Since (A) is the intermediate reactive species whose concentration is determined from equilibrium step.

Slow step is:

A + B2→AB+B (slow)

r = k[A][B2]

From equilibrium step

A2⇌A+A(fast)

keq=[A2][A]2

∴[A]=(keq[A2]1/2

Substitute the value of [A] in equation (i),

r=k.keq1/2[A2]1/2[B2]

Thus, order of reaction = 21+1=121