Given the equation: 2H +02___2H2O
How many moles of 0, would be needed to react 58.5 g of H, to form water? (c) How many grams of H, would be needed to form 120 g of H,0?
Answers
Answer:
i don't known byby by by by
Answer:
1. Oxygen.
Explanation:
Start by taking a look at the balanced chemical equation for this reaction
2
H
2(g]
+
O
2(g]
→
2
H
2
O
(l]
Notice that you have a
2
:
1
mole ratio between hydrogen gas and oxygen gas.
This means that, regardless of how many moles of oxygen gas you have, the reaction needs twice as many moles of hydrogen gas in order to proceed.
You know that you start with
10.0 g
of hydrogen gas nad
15.0 g
of oxygen. To determine how many moles of each you have, use their respective molar masses
10.0
g
⋅
1 mole H
2
2.0159
g
=
4.961 moles H
2
and
15.0
g
⋅
1 mole O
2
32.0
g
=
0.4688 moles O
2
Notice that you have quite a significant difference, way bigger than the required
2
:
1
ratio needed, between how many moles of hydrogen gas and how many moles of oxygen you have.
This means that you're dealing with a limiting reagent. How many moles of oxygen would have been needed to react with all the hydrogen?
4.961
moles H
2
⋅
1 mole O
2
2
moles H
2
=
2.4805 moles O
2
Since you don't have that many moles of oxygen, it follows that oxygen is your limiting reagent, i.e. it will determine how much hydrogen reacts and how much remains in excess.
For example, how many moles of hydrogen gas would react if you have
0.4688
moles of oxygen?
0.4688
moles O
2
⋅
2
moles H
2
1
mole O
2
=
0.9376 moles H
2
The rest of the hydrogen will be in excess.
2. Because Hydrogen and Oxygen react in a 2:1 molar ratio to form water, you need to know how many moles of Hydrogen gas are contained in 58.5 g of H2. Because of the 2:1 H2:O2 molar ratio, divide the moles of H2 by 2 to get the number of moles O2 = 14.286 moles O2. Rounded to 3 sig. fig, the value is 14.3 moles O2.
3. 13.34 gram H2
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