Question

Given the equation of a regression line as y = 1.2x - 3.4. What is residual for point (12, 10)?

Answer 1

Answer:1

Step-by-step explanation:y=1.2X-3.4

                                            10=1.2x12-3.4

                            10=14.4-3.4

11-10=1

Answer 2

The residual for point (12, 10) is -1.

Step-by-step explanation:

The equation of regression line is

$y=1.2x-3.4$

We need to find the residual for point (12, 10).

The given point is (12,10). It means actual value at x=12 is 10.

Substitute x=12 in the given equation.

$y=1.2(12)-3.4$

$y=14.4-3.4$

$y=11$

The value of regression line is 11 at x=12. It means expected value at x=12 is 11.

Residual = Actual - Expected

              = 10 - 11

              = -1

Therefore, the residual for point (12, 10) is -1.

#Learn more

A scatter plot containing the point (12, 12) has the regression equation yˆ=14x+1.

What is the residual e when x = 12?

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