Given the equilibrium constants for the following two reactions in aqueous solution at 25 ∘C HNO2(aq)H2SO3(aq)⇌⇌H+(aq) + NO2−(aq)2H+(aq) + SO32−(aq)Kc = 4.5 × 10−4Kc = 1.1 × 10−9 what is the value of Kc for the reaction 2HNO2(aq) + SO32−(aq)⇌H2SO3(aq) + 2NO2−(aq)
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Explanation:- 12 - 17 को घटाने पर कौन सी संख्या प्राप्त होगी
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Explanation:
The equilibrium reactions in aqueous solution are :
(1)
(2)
The final equilibrium reaction is :
Now we have to calculate the value of for the final reaction.
Now equation 1 is multiply by 2 and reverse the equation 2, we get the value of final equilibrium reaction and the expression of final equilibrium constant is:
Now put all the given values in this expression, we get :
Therefore, the value of for the final reaction is, 184.09
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