Chemistry, asked by hmk243874, 16 days ago

Given the equilibrium constants for the following two reactions in aqueous solution at 25 ∘C HNO2(aq)H2SO3(aq)⇌⇌H+(aq) + NO2−(aq)2H+(aq) + SO32−(aq)Kc = 4.5 × 10−4Kc = 1.1 × 10−9 what is the value of Kc for the reaction 2HNO2(aq) + SO32−(aq)⇌H2SO3(aq) + 2NO2−(aq)

Answers

Answered by khusnumaq14
0

Explanation:- 12 - 17 को घटाने पर कौन सी संख्या प्राप्त होगी

Answered by pinkyrani98760
0

Answer:

Explanation:

The equilibrium reactions in aqueous solution are :

(1)          

(2)          

The final equilibrium reaction is :

       

Now we have to calculate the value of  for the final reaction.

Now equation 1 is multiply by 2 and reverse the equation 2, we get the value of final equilibrium reaction and the expression of final equilibrium constant is:

Now put all the given values in this expression, we get :

Therefore, the value of  for the final reaction is, 184.09

Similar questions