Question

Given the finite sets A and B such that n(A) = 2, n(B)= 3
Then total number of relations from A to B is​

Answer 1

Answer:

ans=2⁶

explanation

if set A contains m elements ans set B contains n elements

then the cartesian product (A×B) contains mn elements

a relation from A to B  is a subset of A×B. hence the number of relations is equal to the number of subsets which is equal to 2power of mn

Answer 2

The total number of relations from A to B is​ 64.

Step-by-step explanation:

A set is well defined collection of objects.

For any two finite sets E and F , such that n(E) = m (E has m elements)and n(F)=n (F has n elements) then

The total number of relations from E to f is $2^{mn}$

Given :  The finite sets A and B such that n(A) = 2, n(B)= 3

Then total number of relations from A to B is​ $2^{2\times3}$

$=2^6=64$

Therefore , the total number of relations from A to B is​ 64.

# Learn more :

Let A and B two finite sets such that n(A)=20,n(B)=28 and n(AUB)=36,find n(A n B).

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