Question

Given the following equation: NaCl + AgNO3 → AgCl + NaNO3 How many gms of AgCl will be produced from 7.00 g of NaCl and 95.0 g of AgNO3 ?

Answer 1

Answer:

25. 025 GRAM AGCL.

Explanation:

IN THE EQUATION, MASS OF NACL= 7 GRAM.

MOLAR MASS = 40 GRAM.

MOLES OF NACL= 7/40 MOLES.

MASS OF AGNO3 = 95 GRAM

MOLAR MASS = 170 GRAM.

SO MOLES OF AGNO3= 95/ 170= 19/ 34 MOLES.

NOW LIMITING REAGENT ON LHS IS NACL SINE ITS MOLE RATIO IS LEAST.

SO MOLES OF AGCL FORMED = 1/1 X 7/40 =7/40 MOLES AGCL.

NOW MOLAR MASS OF AGCL = 143 GRAM.

SO MASS OF AGCL= MOLES X MOLAR MASS= 7/40 X 143 = 25. 025 GRAM AGCL.