Given the following information, calculate the heat of formation of C2H4Cl2(g) in kJ/mole:
2 C(s) + 2 H2(g) + Cl2(g) →C2H4Cl2(g)
2 C(s) + 2 H2(g) →C2H4(g) deltaH/kJ = +52.3 Kj
C2H4Cl2(g) → Cl2(g) + C2H4(g)
DeltaH/kJ= +116/kJ
A. -64
B. +64
C. -168
D. +168
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