Question

Given the following information: N = 100, ∑ (x – 98) = 50, ∑ (x – 98)2 = 1970; ∑ (x – 98)3 = 2948, and ∑ (x – 98)4 = 86752. Find first four central moments. Do you think that the distribution is platykurtic?

Answer 1

Answer:

$m1 = \frac{50}{100} = 0.5 \\ m2 = \frac{1970}{100} = 19.7 \\ m3 = \frac{2948}{100} = 29.48 \\ m4 = \frac{86752}{100} = 867.52 \\ platyurtic \: distribution$

Answer 2

Answer:

okk

Step-by-step explanation:

Answer:

\begin{gathered}m1 = \frac{50}{100} = 0.5 \\ m2 = \frac{1970}{100} = 19.7 \\ m3 = \frac{2948}{100} = 29.48 \\ m4 = \frac{86752}{100} = 867.52 \\ platyurtic \: distribution\end{gathered}

m1=

100

50

=0.5

m2=

100

1970

=19.7

m3=

100

2948

=29.48

m4=

100

86752

=867.52

platyurticdistribution