Question

Given the following reaction:


CH_4 + 2O_2 → CO_2 + 2H_2O


How many moles of CO_2 will be produced from 72.0 g of CH_4 assuming O_2 is available in excess?

Answer 1

Answer:

your answer will be 4.5 mol

Explanation:

if you do by the method of stoichiometry then already in question it is given that $O_{2}$ is excess reagent therefore it is clear that $CH_{4}$ is limiting reagent

therefore mass of methane is given (72 g) and molar mass is 16 g therefore

n=w/m

n=4.5mol

so here to satisfy the conservation of mass we got the no. of moles of carbon dioxide as 4.5 MOLES

hope your doubt has been clear now