Question

Given the following thermochemical equations:


S(rhombic) + O2(g) →SO2 (g) ,∆H = −297.5 kJ mol-1

S(monoclinic) +O2 → SO2 (g) , ,∆H = −300.0 kJ mol-1


Calculate ∆H for the transformation of one gram atom of rhombic sulphur into monoclinic sulphur.​

Answer 1

Answer:

We aim at S (rhombic) → S (monoclinic), ΔH = ? Equation (i)→ Equation (ii) gives S(rhombic) → S(monoclinic) → 0, ΔH = 297.5 → (–300.0) = 2.5 kJ mol–1 or S(rhombic) → S(monoclinic), ΔH = + 2.5 kJ mol–1 Thus, for the transformation of one gram atom of rhombic sulphur into monoclinic sulphur, 2.5 kJ mol–1 of heat is absorbed.

Answer 2

Answer:

ok thanks

Explanation:

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