Given the function ƒ(x )=x^2 + 2x -5, find ƒ(-4).
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f(-4)=-4^2+2*4-5
=16+8-5
=24-5
=19
=16+8-5
=24-5
=19
tamekanstiltner:
Wouldn't it be f(-4)=-4^2+2*-4-5??
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