Question

given the function h(x) = px2 + qx + 7 and that h(3) = 64 and h(-9) = 79 find the value of p and q. Hence evaluate h(7), h(-3) and h(0).
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Answer 1

Answer:

f(x)=x  

4

−62x  

2

+ax+9

f  

′

(x)=4x  

3

−124x+a

f attains its maximum value on the interval [0,2] at x=1.

Therefore,

f  

′

(1)=0

4−124+a=0

a=120

Hence, the value of a is 120.

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