Question

Given the General equation -2y2+3x+12y-15=0 What conic can be formed?​

Answer 1

Step-by-step explanation:

−2y2+3x+12y−15=0

Step 1: Add 2y^2 to both sides.

−2y2+3x+12y−15+2y2=0+2y2

3x+12y−15=2y2

Step 2: Add -12y to both sides.

3x+12y−15+−12y=2y2+−12y

3x−15=2y2−12y

Step 3: Add 15 to both sides.

3x−15+15=2y2−12y+15

3x=2y2−12y+15

Step 4: Divide both sides by 3.

3x

3

=

2y2−12y+15

3

x=

2

3

y2−4y+5

Answer:

x=

2

3

y2−4y+5

Answer 2

Given the General equation -2y2+3x+12y-15=0 What conic can be formed?

firstyly we have to write formula ...

only then we solve it