given the linear equation 3x+4y=9. write another linear equation in these two variables such that the geometrical representation of the pair so formed is
1.intersecting lines 2.coincident lines
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Answered by
49
Answer:
1) Intersecting lines
a1/a2≠b1/b2
another equation can be:
5x-9y=2 ; 3x+4y=9 or
7x+5y=3 ; 3x+4y=9
2) coincident lines
a1/a2=b1/b2=c1/c2
another equation can be:
6x+8y=18 ; 3x+4y=9 or
9x+12y=27 ; 3x+4y=9
Answered by
3
Answer:
1. Intersecting lines
x1/x2 ≠ y1/y2
Here, x1=3 and y1= 4
So, the second linear equation can be
3x-12y=26.
{Here, 3/3 ≠4/(-12)}
9x +7y = (-90)
{Here, 3/9 ≠ 4/7}
2. Coincident limes
x1/x2 = y1/y2 = constant1 / constant2
Here, x1=3, y1 = 4 and constant =(-9)
[Since + sign of 9 becomes - sign on transposing ]
So, the second linear equation can be
12x +16y=36 or 12x+16y-36=0
{Here 3/12 =4/16= 9/36}
-9x-12y=(-27) or -9x-12y+27=0.
{Here, 3/(-9)= 4/(-12)= 9/(-27)}
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