Question

Given the linear equation x+2y+1=0x+2y+1=0, if another pair formed is 2x+4y−3=02x+4y−3=0.then solution of the equations is​

Answer 1

Answer:

2x+y=6

⟹y=6−2x

Let, x=1, then y=6−2(1)=4

Similarly, when x=2,y=2

x−2y+2=0

⟹x=2y−2

Let, y=0, then x=2(0)−2=−2

Similarly, when y=2,x=2

Plotting the above points on the graph, we get, the vertices of the traingle, i.e. A(2,3),B(3,0),C(−2,0)

∴ Area of the triangle =  

2

1

​  

×5units×2units

=5 sq. units

Step-by-step explanation: