Question

given the mass of electron is 9.11 ×10^- 31 kg planck constant is 6.626×10^- 34 joule the uncertainty involved in the measurement of velocity within the distance of 0.1 angstrom is

Answer 1

» According to Heisenberg's uncertainty Principle :-

=> Δx.mΔv ≥ h/4π

Where

Mass of electron

$= > m _{e} = 9.11 \times {10}^{ - 31} \: kg$
$= > h = 6.626 \times {10}^{ - 34} \: kg$
_____________

therefore :-

=> Δv ≥ h/4πmΔx

$\geqslant \: \frac{6.626 \times {10}^{ - 34} }{4 \times 3.14 \times 9.11 \times {10}^{ - 31} \times 0.1 \times {10}^{ - 10} } \\ \\ \geqslant 0.579 \times {10}^{7} \: m {s}^{ - 1}$
=> Δv ≥ 5.79 × 10^6 ms^-1
_____________[ANSWER]

_-_-_-_☆$BE \: \: \: \: BRAINLY$☆_-_-_-_

Answer 2

Given : The mass of electron is

kg, planck constant is

Js, the uncertainty involved in the measurement of velocity within a distance of 0.1 Å is