Question

given:the mass of electron is 9.11×10^_31 kg.planck's constant is 6.626×10^_34js.the uncertainty involved in the measurement of velocity within a distance of .1A°​

Answer 1

Answer:

Explanation:

By heisenberg's uncertainty principle

Δp→ uncertainty in momentum

Δx→ uncertainty in position

Δv→ uncertainty in velocity

m→ mass of particle

Given,

Δx=0.1A=0.1×10^−10m

m=9.11×10^−31kg

h = planck constant =6.626×10^−34js

π=3.14

In uncertain position Δv.Δx=h/4πm

Δv×0.1×10^−10=6.626×10^−34/4×3.14×9.11×10^−31

Δv=6.626×10^−34/4×3.14×9.11×10^−31

=5.785×10^6ms−1

=5.76×10^6ms−1