given:the mass of electron is 9.11×10^_31 kg.planck's constant is 6.626×10^_34js.the uncertainty involved in the measurement of velocity within a distance of .1A°
Answers
Answered by
2
Answer:
Explanation:
By heisenberg's uncertainty principle
Δp→ uncertainty in momentum
Δx→ uncertainty in position
Δv→ uncertainty in velocity
m→ mass of particle
Given,
Δx=0.1A=0.1×10^−10m
m=9.11×10^−31kg
h = planck constant =6.626×10^−34js
π=3.14
In uncertain position Δv.Δx=h/4πm
Δv×0.1×10^−10=6.626×10^−34/4×3.14×9.11×10^−31
Δv=6.626×10^−34/4×3.14×9.11×10^−31
=5.785×10^6ms−1
=5.76×10^6ms−1
Similar questions