Given the mass of the moon = 7.35 × 1022 kg and the radius of the moon = 1740 km. Calculate the acceleration experienced by a particle on the surface of the moon due to the gravitational force of the moon. Find the ratio of this acceleration to that experienced by the same particle on the surface of the earth.
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Answer:
Substituting the values in the formula we get-
g=6.67×10−11×7.35×1022(1.74×106)2
Thus, the value of g on moon is g=1.625 m/s2.
Explanation:
The acceleration experienced by a freely falling object due to the gravitational force of the massive body is called acceleration due to gravity and is represented by g measured using SI unit m/s2. The value of g depends on the mass of the massive body and its radius and its value varies from one body to another. The value of g on moon is constant.
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