Question

Given the maximum of 100 digits number as input,find the difference between sum of oddd and even postion digits in c

Answer 1

A c program for a given a maximum 100 digit number as input:

void getSum(int n)  

{  

//    n = reverse(n);  

int rev = 0;  

while (n != 0)  

{  

     rev = (rev * 10) + (n % 10);  

     n /= 10;  

    }  

   n = rev;  

   int sumofOdd = 0, sumofEven = 0, c = 1;  

 

   while (n != 0) {  

 

       if (c % 2 == 0)  

           sumofEven += n % 10;  

       else

           sumofOdd += n % 10;  

       n /= 10;  

       c++;  

 

   cout << "Sum odd numbers = " << sumOdd << "\n";  

   cout << "Sum even numbers = " << sumEven;