Given the minimum force applied in parallel to the liquid to move an object of mass 100 g in the microscopic area, the material coefficient of friction is 0.4
Answers
Answered by
2
Given:
Given the minimum force applied in parallel to the liquid to move an object of mass 100 g in the microscopic area, the material coefficient of friction is 0.4
To find:
The minimum force applied.
Solution:
From given, we have,
The mass of object = m = 100 g
The coefficient of friction = μ = 0.4
As the minimum force applied in parallel to the liquid, so we have, θ = 0°
we use the formula,
f = μmg cos θ
f = 0.4 × 100 × 9.8 × cos 0°
f = 392 N
Therefore, the minimum force applied is 392 N
Similar questions