Question

Given the network address below, find the class, the block and the range of the addresses

a. 17.0.0.0

b. 132.21.0.0

c. 220.34.76.0

Answer 1

Hey there!

----------

Answer :

(a) 17.0.0.0

⇒ The first byte is 17 (between 0 - 127); the class is A.

The blocks in Class A has a netid of 17. Therefore, The address range is of from 17.0.0.0 to 17.255.255.255.

{Netid 0 = 0.0.0.0 - 0.255.255.255}

(b) 132.21.0.0

⇒ The first byte is 132 (between 128 - 191); the class is B.

The blocks in Class B has a netid of 132.21. Therefore, the address range is of from 132.21.0.0 to 132.21.255.255.

{Netid 180.8 = 180.8.0.0 - 180.8.255.255}

(c) 220.34.76.0

⇒ The first byte is 220 (between 192 - 223); the class is C.

The blocks in Class C has a netid of 220.34.76. Therefore, the address range is of from 220.34.76.0 to 220.34.76.255.

{Netid 200.11.8 = 200.11.8.0 = 200.11.8.255}